Given: The correct term is 250 ( a - b )³ + 2.
To find: The factorisation for the algebra given?
Solution:
Now we have given the term as: 250 ( a - b )³ + 2
Taking 2 common, we get:
2 { 125 ( a - b )³ + 1 }
Now we can write 125 as 5³, we get:
2 { 5³( a - b )³ + 1 }
Now combining 5³ and (a - b)³, we get:
2 { ( 5a - 5b )³ + 1³ }
Now solving further we get:
2 (5a - 5b + 1) { (5a - 5b)² - (5a - 5b) x 1 + 1² }
2 (5a - 5b + 1) (25a² - 50ab + 25b² - 5a + 5b + 1)
So this is the required factorisation.
Answer:
So the factorisation of 250 ( a - b )³ + 2 is
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Answers & Comments
Given: The correct term is 250 ( a - b )³ + 2.
To find: The factorisation for the algebra given?
Solution:
Now we have given the term as: 250 ( a - b )³ + 2
Taking 2 common, we get:
2 { 125 ( a - b )³ + 1 }
Now we can write 125 as 5³, we get:
2 { 5³( a - b )³ + 1 }
Now combining 5³ and (a - b)³, we get:
2 { ( 5a - 5b )³ + 1³ }
Now solving further we get:
2 (5a - 5b + 1) { (5a - 5b)² - (5a - 5b) x 1 + 1² }
2 (5a - 5b + 1) (25a² - 50ab + 25b² - 5a + 5b + 1)
So this is the required factorisation.
Answer:
So the factorisation of 250 ( a - b )³ + 2 is
2 (5a - 5b + 1) (25a² - 50ab + 25b² - 5a + 5b + 1)