There is a building of height 180m, a ball is drop from the top and allowed to fall under the acceleration due gravity another ball is thrown just after 2 seconds with the initial velocity of 'u'. If both the balls meet after 100m of distance from top. Find 'u'.
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Step-by-step explanation:
S = ut +1/2at²
100 = u(2) +1/2×9.8×2²
100 = 2u + 4.9×4
100 - 19.6 = 2u
2u = 80.4
u = 40.2 m/s