Answer:AnswerNumber of atoms in close packaging = 0.5 mol1 has 6.022×10 23 particlesSo thatNumber of close-packed particles=0.5×6.022×10 23 =3.011×10 23 Number of tetrahedral voids = 2 × number of atoms in close packagingPlug the values we getNumber of tetrahedral voids =2×3.011×10 23 =6.022×10 23 Number of octahedral voids = number of atoms in close packagingSo thatNumber of octahedral voids =3.011×10 23 Total number of voids = Tetrahedral void + octahedral void =6.022×10 23 +3.011×10 23 =9.03×10 23
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Answer:
Answer:AnswerNumber of atoms in close packaging = 0.5 mol1 has 6.022×10 23 particlesSo thatNumber of close-packed particles=0.5×6.022×10 23 =3.011×10 23 Number of tetrahedral voids = 2 × number of atoms in close packagingPlug the values we getNumber of tetrahedral voids =2×3.011×10 23 =6.022×10 23 Number of octahedral voids = number of atoms in close packagingSo thatNumber of octahedral voids =3.011×10 23 Total number of voids = Tetrahedral void + octahedral void =6.022×10 23 +3.011×10 23 =9.03×10 23
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