Answer:
Answer
Number of atoms in close packaging = 0.5 mol
1 has 6.022×10
23
particles
So that
Number of close-packed particles
=0.5×6.022×10
=3.011×10
Number of tetrahedral voids = 2 × number of atoms in close packaging
Plug the values we get
Number of tetrahedral voids =2×3.011×10
=6.022×10
Number of octahedral voids = number of atoms in close packaging
Number of octahedral voids =3.011×10
Total number of voids = Tetrahedral void + octahedral void
+3.011×10
=9.03×10
Explanation:
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Answers & Comments
Answer:
Answer
Number of atoms in close packaging = 0.5 mol
1 has 6.022×10
23
particles
So that
Number of close-packed particles
=0.5×6.022×10
23
=3.011×10
23
Number of tetrahedral voids = 2 × number of atoms in close packaging
Plug the values we get
Number of tetrahedral voids =2×3.011×10
23
=6.022×10
23
Number of octahedral voids = number of atoms in close packaging
So that
Number of octahedral voids =3.011×10
23
Total number of voids = Tetrahedral void + octahedral void
=6.022×10
23
+3.011×10
23
=9.03×10
23
Explanation:
ARE 'SHINCHAN0824' LA AJUN FO.LLOW KARTOS
PN MI TI I.D VAPARU SHAKT NAHI YAAR