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bubra
@bubra
October 2021
1
23
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the filament of a 240 V ,100W electric bulb heats up the room temperature .as it heats up its resistance increases by a factor of 16 what is the resistance of this bulb temperature
Answers & Comments
selfy
Best Answer
...
R at operating temp
P = V^2 / R
100 = 240^2 / R
R = 576 ohm
then take 1/16th of that
576/16 = 36 ohm
0 votes
Thanks 2
bubra
thank you sooooooooooo much
selfy
mark it as brainliest
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Answers & Comments
...
R at operating temp
P = V^2 / R
100 = 240^2 / R
R = 576 ohm
then take 1/16th of that
576/16 = 36 ohm