a beam of alpha particles and protons of some velocity enter in uniform magnetic field at the right angle the ratio of radii of two paths are
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Proton will be hydrogen of charge 1e and mass 1u
Radius of circle of charged particle in magnetic field will be r=mv/qb
By lorentz force,
Radius=momemtum /charge *magnetic field
WE know that radius is inversly proportional to charge
SO Radius of alpha particle will be half of radius of proton
Hence Radii =1:2
Answer:
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Explanation:
Alpha particles will be helium nucleus of charge 2e and mass 4u
Alpha particles will be helium nucleus of charge 2e and mass 4uProton will be hydrogen of charge 1e and mass 1u
Alpha particles will be helium nucleus of charge 2e and mass 4uProton will be hydrogen of charge 1e and mass 1uRadius of circle of charged particle in magnetic field will be r=mv/qb
Alpha particles will be helium nucleus of charge 2e and mass 4uProton will be hydrogen of charge 1e and mass 1uRadius of circle of charged particle in magnetic field will be r=mv/qbBy lorenzo force ,
Alpha particles will be helium nucleus of charge 2e and mass 4uProton will be hydrogen of charge 1e and mass 1uRadius of circle of charged particle in magnetic field will be r=mv/qbBy lorenzo force ,Radius = Momentum /charge *magnetic field
Alpha particles will be helium nucleus of charge 2e and mass 4uProton will be hydrogen of charge 1e and mass 1uRadius of circle of charged particle in magnetic field will be r=mv/qbBy lorenzo force ,Radius = Momentum /charge *magnetic field We know that radius is inversely proportional to charge
Alpha particles will be helium nucleus of charge 2e and mass 4uProton will be hydrogen of charge 1e and mass 1uRadius of circle of charged particle in magnetic field will be r=mv/qbBy lorenzo force ,Radius = Momentum /charge *magnetic field We know that radius is inversely proportional to chargeSo radius of alpha particles will be half of radius of proton
Alpha particles will be helium nucleus of charge 2e and mass 4uProton will be hydrogen of charge 1e and mass 1uRadius of circle of charged particle in magnetic field will be r=mv/qbBy lorenzo force ,Radius = Momentum /charge *magnetic field We know that radius is inversely proportional to chargeSo radius of alpha particles will be half of radius of protonHence radiii=1:2