a certain wire has a radius R another wire of same resistance,has half the length and half the diameter of the first wire.the resistance of second wire is
Answers & Comments
abhinavthottamk
R1/R2=(l1×r2^2)÷(l2×r1^2) Given l2=l1/2 Diameter=2×radius D2=D1/2 means r2=r1/2 Substituting we get R1/R2= 8 R1/8=R2 It's 1/8th times oof first wire
Answers & Comments
Given l2=l1/2
Diameter=2×radius
D2=D1/2 means r2=r1/2
Substituting we get
R1/R2= 8
R1/8=R2
It's 1/8th times oof first wire
Answer:
.the resistance of second wire is 0.25 R
Explanation:
for explanation see the attached photo