Answer:
1.
Just copy the denominator because it has the similar between in the denominator
Add the numerator
so the answer is
2.
SIMPLIFYING
FACTORED FORM
Cancelled the x + 5 because it has a similarities
so the final answer is x - 5
3.
FIND THE LCD OF
The lcm 6x
6x divided by 6x is 1
1 × 1 = 1
6x divided by 3x is 2
2 × 1 = 2
ADD THE NUMERATOR
÷
4.
The lcm 5x
5x divided by 5 is x
x × 2 = 2x
5x divided by 5x is 1
5. × =
times the numerator
2 × y = 2y
times the denominator
3 × x = 3x
6. ×
SOLUTION
cancelled the y + 3
SIMPLIFYING THE FARCTION
÷ =
so the answer is 1/2
7. × =
8. ÷
Cancelled the 5 and x - 2 because it has similar
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Answers & Comments
Answer:
1.
![\frac{7}{x+8} \frac{7}{x+8}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7Bx%2B8%7D)
SOLUTION
Just copy the denominator because it has the similar between
in the denominator
Add the numerator
so the answer is![\frac{7}{x+8} \frac{7}{x+8}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7Bx%2B8%7D)
2.
SOLUTION
Just copy the denominator because it has the similar between
in the denominator
SIMPLIFYING
FACTORED FORM
Cancelled the x + 5 because it has a similarities
so the final answer is x - 5
3.![\frac{1}{3x} + \frac{1}{6x} = \frac{1}{2x} \frac{1}{3x} + \frac{1}{6x} = \frac{1}{2x}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3x%7D%20%2B%20%5Cfrac%7B1%7D%7B6x%7D%20%3D%20%5Cfrac%7B1%7D%7B2x%7D)
SOLUTION
FIND THE LCD OF![\frac{1}{3x} and \frac{1}{6x} \frac{1}{3x} and \frac{1}{6x}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3x%7D%20and%20%5Cfrac%7B1%7D%7B6x%7D)
The lcm 6x
6x divided by 6x is 1
1 × 1 = 1
6x divided by 3x is 2
2 × 1 = 2
ADD THE NUMERATOR
SIMPLIFYING
so the answer is![\frac{1}{2x} \frac{1}{2x}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2x%7D)
4.![\frac{2}{5} - \frac{1}{5x} = \frac{2x-1}{5x} \frac{2}{5} - \frac{1}{5x} = \frac{2x-1}{5x}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%20-%20%5Cfrac%7B1%7D%7B5x%7D%20%3D%20%5Cfrac%7B2x-1%7D%7B5x%7D)
SOLUTION
FIND THE LCD OF![\frac{2}{5} and \frac{1}{5x} \frac{2}{5} and \frac{1}{5x}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%20and%20%5Cfrac%7B1%7D%7B5x%7D)
The lcm 5x
5x divided by 5 is x
x × 2 = 2x
5x divided by 5x is 1
1 × 1 = 1
so the answer is![\frac{2x-1}{5x} \frac{2x-1}{5x}](https://tex.z-dn.net/?f=%5Cfrac%7B2x-1%7D%7B5x%7D)
5.
×
= ![\frac{2y}{3x} \frac{2y}{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B2y%7D%7B3x%7D)
SOLUTION
times the numerator
2 × y = 2y
times the denominator
3 × x = 3x
so the answer is![\frac{2y}{3x} \frac{2y}{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B2y%7D%7B3x%7D)
6.
× ![\frac{(y+3)}{2x+8} = \frac{1}{2} \frac{(y+3)}{2x+8} = \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%28y%2B3%29%7D%7B2x%2B8%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
SOLUTION
cancelled the y + 3
SIMPLIFYING THE FARCTION
so the answer is 1/2
7.
×
= ![\frac{2y}{3x} \frac{2y}{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B2y%7D%7B3x%7D)
SOLUTION
times the numerator
2 × y = 2y
times the denominator
3 × x = 3x
so the answer is![\frac{2y}{3x} \frac{2y}{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B2y%7D%7B3x%7D)
8.
÷ ![\frac{5}{( x-2 )} = \frac{4}{x+2} \frac{5}{( x-2 )} = \frac{4}{x+2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B%28%20x-2%20%29%7D%20%3D%20%5Cfrac%7B4%7D%7Bx%2B2%7D)
SOLUTION
FACTORED FORM
Cancelled the 5 and x - 2 because it has similar
so the answer is![\frac{4}{x+2} \frac{4}{x+2}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7Bx%2B2%7D)
sana po makatulong po :)
add or follow on my acc
please mark my answer brainliest :)
#CarryOnLearning
- PANDA8840