In the given figure if AP= 2 cm , BQ =3 cm and RC= 4 cm, then calculate the perimeter of ∆ ABC.
(Class 10 Maths Sample Question Paper)
(Class 10 Maths Sample Question Paper)
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FIGURE IS IN THE ATTACHMENT.Given:
AP = 2 cm
BQ = 3 cm
RC = 4 cm
AP = AR = 2 cm
BQ = BP =3 cm
RC = CQ = 4 cm
(We know that two tangents drawn from an external point to the circle are equal in length.)
AB = AP + BP = 2 + 3 = 5 cm
BC = BQ + CQ = 3 + 4= 7 cm
CA = CR + AR = 4 +2 = 6 cm
Perimeter of ∆ ABC = AB + BC + CA
Perimeter of ∆ ABC = 5 + 7 + 6 = 18 cm.
Hence, the Perimeter of ∆ ABC = 18 cm.
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Answer:
4cm
Step-by-step explanation:
We have two chords AB and CD intersect at P ,
AP = 2 cm , BP = 6 cm , CP = 3 cm
We know " Theorem : When two chords intersect each other inside or outside of the circle , The rectangle formed by two segment of one chord is equal in Area of rectangle formed by two segment of other chord . "
So , we get
AP × BP = CP × DP
So, substitute all values , we get
2 × 6 = 3 × DP
3 DP = 12
DP = 4
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