9.) The area of the rectangle is x2 – 3x - 10. What is its length if its width is x + 2?
a.) (x + 5)(x-2)
c.) x + 5/ X-2
b.) (x + 5 XX-2
d.) x-5
a.) (x + 5)(x-2)
c.) x + 5/ X-2
b.) (x + 5 XX-2
d.) x-5
Add an Answer
More Questions From This User See All
Answers & Comments
Problem:
The area of the rectangle is x2 – 3x - 10. What is its length if its width is x + 2?
Solution:
A = x² - 3x - 10
W = (x + 2)
A = LW
x² - 3x - 10 = (x + 2) (L)
L = (x² - 3x - 10) / (x + 2)
L = (x - 5)(x + 2) / (x + 2)
L = (x - 5)
Answer:
Length = (x - 5)
#CarryOnLearning