Answer:
AB×CB=DDD
Now DDD has a factor of D or 111
111 has factor 3 or 37
DDD=37×3×D=AB×CB
Thus either AB and CB is 37 and other number is 3\times D.
D=9
37×(3×9)=999
37×27=999
A=3,B=7,C=2,d=9
A+B+C+D=3+7+2+9=21
Sorry brotha these are the only ones I can answer. I hope this hel you even just a lil bit though also
#carryonlearning CAUSE I HEARD WE HAVING EXAMS AT THE END OF THE QUARTER THIS TIME
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Answer:
AB×CB=DDD
Now DDD has a factor of D or 111
111 has factor 3 or 37
DDD=37×3×D=AB×CB
Thus either AB and CB is 37 and other number is 3\times D.
D=9
37×(3×9)=999
37×27=999
A=3,B=7,C=2,d=9
A+B+C+D=3+7+2+9=21
Sorry brotha these are the only ones I can answer. I hope this hel you even just a lil bit though also
#carryonlearning CAUSE I HEARD WE HAVING EXAMS AT THE END OF THE QUARTER THIS TIME