Answer:
Basically , net force is known as resultant force and is a vector quantity.
In the Attachment b) it is net resulant force because they both boys are pulling it.
In the Attachment a ) It's difficult to say that it's net resulant or not .
Because from both sides the boys are pulling and wasting their energy.
Hence, attachment b is a net resulant force in the situations given below .
Answer
(a) 0 N
(b) 2F N
Given
Case - 1 :
Case - 2 :
To Find
Solution
→ Case - 1 : (a)
[ Assume that forces exerted by two boys will be same i.e., F ]
Let the force exerted by boy 1 be F₁
⇒ F₁ = F
[ ∵ He pulls cart in + ve direction ]
Let the force exerted by boy 2 be F₂
⇒ F₂ = - F
[ ∵ He pulls cart in - ve direction ]
So ,
Net resultant force ,
→ Case - 2 : (b)
⇒ F₂ = F
[ ∵ He too pulls cart in + ve direction ]
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Answers & Comments
Answer:
Basically , net force is known as resultant force and is a vector quantity.
In the Attachment b) it is net resulant force because they both boys are pulling it.
In the Attachment a ) It's difficult to say that it's net resulant or not .
Because from both sides the boys are pulling and wasting their energy.
Hence, attachment b is a net resulant force in the situations given below .
Answer
(a) 0 N
(b) 2F N
Given
Case - 1 :
Case - 2 :
To Find
Solution
→ Case - 1 : (a)
[ Assume that forces exerted by two boys will be same i.e., F ]
Let the force exerted by boy 1 be F₁
⇒ F₁ = F
[ ∵ He pulls cart in + ve direction ]
Let the force exerted by boy 2 be F₂
⇒ F₂ = - F
[ ∵ He pulls cart in - ve direction ]
So ,
Net resultant force ,
→ Case - 2 : (b)
[ Assume that forces exerted by two boys will be same i.e., F ]
Let the force exerted by boy 1 be F₁
⇒ F₁ = F
[ ∵ He pulls cart in + ve direction ]
Let the force exerted by boy 2 be F₂
⇒ F₂ = F
[ ∵ He too pulls cart in + ve direction ]
So ,