molarity = 0.380 M
volume of solution = 600 mL = 0.600 L
mass of solute
In this problem, the solute is CaCl₂. Getting the molar mass of solute
molar mass of solute = (40.08 g/mol × 1) + (35.45 g/mol × 2)
molar mass of solute = 110.98 g/mol
Solving for the mass of solute (CaCl₂)
mass of solute = molarity × molar mass of solute × volume of solution
mass of solute = 0.380 M × 110.98 g/mol × 0.600 L
Therefore, 25.3 g of CaCl₂ is needed.
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Note: In solving molarity problems, the volume of the solution must be expressed in liters because a 1-molar solution contains 1 mole of solute in 1 liter of solution.
1 molar (M) = 1 mole per liter (mol/L)
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Answers & Comments
Given:
molarity = 0.380 M
volume of solution = 600 mL = 0.600 L
Required:
mass of solute
Solution:
In this problem, the solute is CaCl₂. Getting the molar mass of solute
molar mass of solute = (40.08 g/mol × 1) + (35.45 g/mol × 2)
molar mass of solute = 110.98 g/mol
Solving for the mass of solute (CaCl₂)
mass of solute = molarity × molar mass of solute × volume of solution
mass of solute = 0.380 M × 110.98 g/mol × 0.600 L
Therefore, 25.3 g of CaCl₂ is needed.
--------------------------------------------------------
Note: In solving molarity problems, the volume of the solution must be expressed in liters because a 1-molar solution contains 1 mole of solute in 1 liter of solution.
1 molar (M) = 1 mole per liter (mol/L)