The standard equation of a circle with the center at (h, k) and a radius of r units is (x – h)²+ (y – k)² = r². Given the cross section which is a circle, find the equation of a circle in standard form with center at (0, -5) and one point on the circle is (2, 3).
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Answer:
x² + (y + 5)² = (√68)²
Step-by-step explanation:
(1) State the given
x1 = 0
y1 = -5
x2 = 2
y2 = 3
(2) Solve for the radius using distance formula
(3) Substitute the coordinates of the center (0,-5) and the obtained r value in the standard form of the equation
(x - h)² + (y - k)² = r²
(x - 0)² + (y -(-5)) = (√68)²
x² + (y + 5)² = (√68)²
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