Answer:

10^-6

Explanation:

I am showing butanoate ion by Bo

The reaction will be in water be like

BoNa + H20---------> BoH + NaoH

BoH is butanoic acid.

Now ph is 9 that mean ph =9

-log [H+] = 9

[H+] = 10^-9

dissociation constant

= conc. of product butanoic acid ÷ conc. of reactant sodium butanoate (0.001M)

conc. of butanoic acid can be taken nearly same to H+

conc.

so we get K= 10^-9 ÷ 10^-3 = 10^-6

Answer:

ans is 10^-6

Explanation:

hope help you