NLM question Consider the arrangement shown. Table top is rough and coefficient of friction between table top and block 2m is μ. Pulley and string are ideal. Minimum value of μ at table top to keep system at equilibrium, is DONT SPAM. Created by sam9876. Physics

NLM question Consider the arrangement shown. Table top is rough and coefficient ...

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{\mu=0.5}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline{\bold{Given :}}} \\ \tt: \implies Mass \: of \: blocks = m \: and \: 2 m \\ \\ \red{\underline{\bold{To \: Find :}}} \\ \tt: \implies Minimum \: value \: of \: \mu \: so \: that \: system \: will \: be \: in \: equilibrium =?$

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$\bold{For \: block \: of \: mass \: m} \\ \tt: \implies mg - T= ma \\ \\ \tt \because \: a = 0 { \: m/s}^{2} \\ \\ \tt: \implies T = mg - - - - - (1) \\ \\ \bold{For \: block \: of \: mass \: 2m} \\ \tt: \implies T = fr \:\:\:\:\:\:(for\:equilibrium) \\ \\ \tt: \implies T= \mu N \\ \\ \tt: \implies t = \mu \: 2mg \\ \\ \tt: \implies mg = \mu \: 2mg \\ \\ \tt: \implies \mu = \frac{mg}{2mg} \\ \\ \green{\tt: \implies \mu = 0.5} \\ \\ \green{ \tt \therefore Minimum \: coefficient \: of \: friction \: is \: 0.5 }$

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