The diameter and length of a roller are 70 cm and 100 cm respectively,. It moves once over to level a playground of area 4400 m.sq. Find the number of revolutions the roller will take to level the playground
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it's length consider as hieght
daimeter is 70 and radius is 35cm
so, it's curved surface area is
=2πrh
=2×22×35×100/7
=22000 cm²
so in m²
=22000/100 m²
=220 m²
if it roll full one time it covers 220 m² area of playground
so,
1:?::220:4400
=4400/220
=20
so it will take 20 revolutions to level the playground
=2*22/7*35*100
=22000 cm .sq
=2.2 m.sq
area of ground = 4400 m.sq
1 revolution cover =2.2 m.sq
how many revolution =4400/2.2
2000 revolution . answer