The average osmotic pressure of blood at 25oC is 7.7atm. How many grams of glucose (C6H12O6) is needed to prepare a 110-L solution that is isotonic with blood at 25oC? with solution please
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Answer:
0.31 mol L
−
1
Explanation:
The problem wants you to determine what concentration of glucose would produce a solution that has the same osmotic pressure as blood at
25
∘
C
.
As you know, osmotic pressure is defined as the pressure required to prevent the flow of water across a semi-permeable membrane from a region of lower solute concentration into a region of higher solute concentration
π= 7.7 atm
i= 1
R= 0.08206 L.atm/mol.K
T= 25 oC (convert to kelvin) 25oC + 273.15 = 298.15 K
M=?
(7.7 atm)/(1 ×0.0821 (L.atm)/(mol.K) ×298.15 K) (cancel same units)
=0.3145667058 mol/L or 0.31 mol/L