1.) What is the boiling point of a solution made by dissolving 31.0 grams of sodium chloride (NaCl) in 559.0 grams of water (H2O)? Note: Kb =0.52 oC/m (This is an Electrolyte solution)
2.) Calculate the freezing point of a nonionizing antifreeze solution containing 388.0 grams of ethylene glycol (C2H6O2), and 409.0 grams of water (H2O).
3.) If 152.0 grams of Na2SO4 are dissolved in 875.0 grams of H2O, what will be the (a) Boiling point and (b) freezing point of the resulting solution? Note: Kb =0.52 oC/m , Kf = 1.86 oC/m. (This is an Electrolyte solution)
4.) A 900 mL aqueous solution contains 30.0 grams of a protein. The osmotic pressure of the solution is 12.7 mm Hg at 25°C. What is the molar mass of the protein?
2.) Calculate the freezing point of a nonionizing antifreeze solution containing 388.0 grams of ethylene glycol (C2H6O2), and 409.0 grams of water (H2O).
3.) If 152.0 grams of Na2SO4 are dissolved in 875.0 grams of H2O, what will be the (a) Boiling point and (b) freezing point of the resulting solution? Note: Kb =0.52 oC/m , Kf = 1.86 oC/m. (This is an Electrolyte solution)
4.) A 900 mL aqueous solution contains 30.0 grams of a protein. The osmotic pressure of the solution is 12.7 mm Hg at 25°C. What is the molar mass of the protein?
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Answer:
1.The new boiling point is 104.46 °C.
Explanation: