[tex] \sf \red{Question:}[/tex]
Shanti Sweets Stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions 25 cm×20cm×5cm and the smaller of dimension 15cm×12cm×5cm. For all the overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is Rs. 4 for 1000 cm², find the cost of cardboard required for supplying 250 boxes of each kind.
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Total S.A of bigger box
=2(lb+bh+lh)
=2(25×20+25×5+20×5) cm 2
=2(500+125+100)
=1450 cm 2
⇒For overlapping extra area required =
100
450×5
=72.5 cm 2
∴ Total S.A (including overlaps)
=1450+72.5=1522.5 cm 2
Area of cardboard sheet for 250 such boxes
=(1522.5×250) cm 2
Total S.A of smaller box
=2(15×12+15×5+12×5)cm 2
=630 cm 2
For overlapping area required =
100
630×5
=31.5 cm 2
Total S.A (including overlaps)=630+31.5=661.5 cm 2
Area of cardboard sheet required for 250 such boxes
=250×661.5cm 2
=165375 cm 2
Total cardboard sheet required =380625+165375
=54000 cm 2
⇒Cost of 1000 cm 2
cardboard sheet = Rs.4
⇒Cost of 546000 cm 2
cardboard sheet
= Rs.
1000
546000×4
= Rs. 2184
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Answer:
rs.2184
Step-by-step explanation:
Total S.A of bigger box = 2(lb + bh+lh)
= 2(25 x 20 +25 × 5 + 20 × 5) cm²
= 2(500 + 125 + 100)
= 1450 cm²
⇒For overlapping extra area required
450 × 5
100
... Total S.A (including overlaps)
= 1450 + 72.5 1522.5 cm²
Area of cardboard sheet for 250 such boxes (1522.5 x 250) cm²
Total S.A of smaller box
= 2(15 x 12+ 15 x 5 + 12 x 5)cm²
= 630 cm²
For overlapping area required
630 × 5
100
Total S.A (including overlaps)
=
630 +31.5 661.5 cm²
= 31.5 cm²
= 72.5 cm²
Area of cardboard sheet required for 250 such
boxes
= 250 x 661.5cm² 165375 cm²
Total cardboard sheet required = 380625 + 165375 54000 cm²
⇒Cost of 1000 cm² cardboard sheet = Rs.4
⇒Cost of 546000 cm² cardboard sheet
546000 × 4
1000
= Rs.
Rs. 2184
hope it help's you