Answer: 88 milliliter water should mix in 12 ml of alcohol so as to obtain 12% of alcohol solution.12
88 milliliter water should mix in 12 ml of alcohol so as to obtain 12% of alcohol solution.
Explanation:
Let the volume of the water be x
Volume of alcohol =12 mL
Volume of the solution = x+12
Percentage of solution = 12% by volume
v/v\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100v/v%=
Mass of solution
Mass of solute
×100
12\%=\frac{12 mL}{x+12mL}\times 10012%=
x+12mL
12mL
x = 88 mL
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Answer: 88 milliliter water should mix in 12 ml of alcohol so as to obtain 12% of alcohol solution.12
88 milliliter water should mix in 12 ml of alcohol so as to obtain 12% of alcohol solution.
Explanation:
Let the volume of the water be x
Volume of alcohol =12 mL
Volume of the solution = x+12
Percentage of solution = 12% by volume
v/v\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100v/v%=
Mass of solution
Mass of solute
×100
12\%=\frac{12 mL}{x+12mL}\times 10012%=
x+12mL
12mL
×100
x = 88 mL
88 milliliter water should mix in 12 ml of alcohol so as to obtain 12% of alcohol solution.