Answer:
1
Step-by-step explanation:
[tex]a + b - c = \: log( \frac{3}{5} ) + log( \frac{5}{4} ) - 2log( \frac{ \sqrt{3} }{2} ) [/tex]
[tex]a + b - c = log( \frac{3}{5} ) + log( \frac{5}{4} ) - log( \frac{3 }{4} ) [/tex]
[tex]a + b - c = log( \frac{3}{5} \times \frac{5}{4} \div \frac{3}{4} ) [/tex]
[tex]a + b - c = log( \frac{3}{5} \times \frac{5}{4} \times \frac{4}{3} ) [/tex]
[tex] a + b - c = log(1) [/tex]
[tex]a + b - c = 0[/tex]
[tex] {15}^{a + b - c} [/tex]
[tex] = {15}^{0} [/tex]
[tex] = 1[/tex]
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
1
Step-by-step explanation:
[tex]a + b - c = \: log( \frac{3}{5} ) + log( \frac{5}{4} ) - 2log( \frac{ \sqrt{3} }{2} ) [/tex]
[tex]a + b - c = log( \frac{3}{5} ) + log( \frac{5}{4} ) - log( \frac{3 }{4} ) [/tex]
[tex]a + b - c = log( \frac{3}{5} \times \frac{5}{4} \div \frac{3}{4} ) [/tex]
[tex]a + b - c = log( \frac{3}{5} \times \frac{5}{4} \times \frac{4}{3} ) [/tex]
[tex] a + b - c = log(1) [/tex]
[tex]a + b - c = 0[/tex]
[tex] {15}^{a + b - c} [/tex]
[tex] = {15}^{0} [/tex]
[tex] = 1[/tex]