Answer:

The intergers are 33 and 99.

Step-by-step explanation:

* let x and y be the integers

* sum means addition, so

x+y=132

* one of the integers is thrice as the other integer means

x=3y

SOLVE: X+Y=132

* substitute 3y to x

* So, it will become

3y+y=132

* simplify

That becomes,

4y=132

* divide both sides by 4 to get the value of the first integer 'y'

4y/4=132/4

y=33

*hence, the first integer 'y' is 33

* To get the other integer 'x', use the first formula and substitute 33 to variable 'y'

X+Y=132

X+33=132

*transpose +33 to the right.

NOTE : We change the sign when we transpose a number or a variable. So we get,

X=132-33

* then

X=99

* the other variable 'x' is 99.

X=99 and Y =33