Answer:

x= -4 and -12

Step-by-step explanation:

Solution by completing the square for:

x^2+16x+48=0

Keep x terms on the left and move

the constant to the right side

by subtracting it on both sides

x^2+16x=−48

Take half of the x term and square it

[16⋅1/2]^2=64

then add the result to both sides

x^2+16x+64=−48+64

Rewrite the perfect square on the left

(x+8)^2=−48+64

and combine terms on the right

(x+8)^2=16

Take the square root of both sides

x+8=±√16

Isolate the x on the left side and

solve for x (1)

x=−8±4

therefore (2)

x=−8+4

x=−8−4

which becomes

x=−4

x=−12