Solve for the BMI of the following given using the formula on page 9 and give
its classification. (Underweight, Normal, Overweight, Obese)
FORMULA
WEIGHT in kilograms
BMI = HEIGHT (in meters)2
1. Weight = 33kg
Height = 1.27 m
2. Weight = 27kg
Height = 1.15 m
3. Weight = 36kg
Height = 1.45 m
4. Weight = 45kg
Height = 1.30 m
5. Weight = 47kg
Height = 1.20 m
Answers & Comments
Answer:
1.![\frac{33kg}{1.27m^2} \frac{33kg}{1.27m^2}](https://tex.z-dn.net/?f=%5Cfrac%7B33kg%7D%7B1.27m%5E2%7D)
=![\frac{33kg}{1.6129m^2} \frac{33kg}{1.6129m^2}](https://tex.z-dn.net/?f=%5Cfrac%7B33kg%7D%7B1.6129m%5E2%7D)
= 20.460
(Normal weight)
2.![\frac{27kg}{1.15m^2} \frac{27kg}{1.15m^2}](https://tex.z-dn.net/?f=%5Cfrac%7B27kg%7D%7B1.15m%5E2%7D)
=![\frac{27kg}{1.3225m^2} \frac{27kg}{1.3225m^2}](https://tex.z-dn.net/?f=%5Cfrac%7B27kg%7D%7B1.3225m%5E2%7D)
= 20.415 (Normal weight)
3.![\frac{36kg}{1.45m^2} \frac{36kg}{1.45m^2}](https://tex.z-dn.net/?f=%5Cfrac%7B36kg%7D%7B1.45m%5E2%7D)
=![\frac{36kg}{2.1025m^2} \frac{36kg}{2.1025m^2}](https://tex.z-dn.net/?f=%5Cfrac%7B36kg%7D%7B2.1025m%5E2%7D)
= 17.122 (under weight)
4.![\frac{45kg}{1.30m^2} \frac{45kg}{1.30m^2}](https://tex.z-dn.net/?f=%5Cfrac%7B45kg%7D%7B1.30m%5E2%7D)
=![\frac{45kg}{1.69m^2} \frac{45kg}{1.69m^2}](https://tex.z-dn.net/?f=%5Cfrac%7B45kg%7D%7B1.69m%5E2%7D)
= 26.627(Pre-Obesity)
5.![\frac{47kg}{1.20m^2} \frac{47kg}{1.20m^2}](https://tex.z-dn.net/?f=%5Cfrac%7B47kg%7D%7B1.20m%5E2%7D)
=![\frac{47kg}{1.44m^2} \frac{47kg}{1.44m^2}](https://tex.z-dn.net/?f=%5Cfrac%7B47kg%7D%7B1.44m%5E2%7D)
= 32.638 (Obesity class 1)
Explanation: You can solve you BMI by following this easy format.
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