Situation 1: Ball B is at rest. 1.a. What will be the velocity of ball B after, if: the collision is perfectly elastic? You may use this formula: A(before)+B(before) = A(after)+B(after) (m)(v) +(m)(v) = (m)(v) +(m)(v)
1. b. What will be the velocity of ball B after, if the collision is perfectly inelastic? You may use this formula: A(before)+B(before) = A(after)+B(after) (m)(v) +(m)(v) = (mA + mB)(v)
Situation 2: Ball B travels twice the velocity of ball A. 2. a. What will be the velocity of ball B after, if: a. the collision is perfectly elastic? You may use this formula: A(before)+B(before) = A(after)+B(after) (m)(v) +(m)(v) = (m)(v) +(m)(v)
2.b. What will be the velocity of ball B after, if the collision is perfectly inelastic? You may use this formula. A(before)+B(before) = A(after)+B(after) (m)(v) +(m)(v) = (mA + mB) (v)
1. b. What will be the velocity of ball B after, if the collision is perfectly inelastic? You may use this formula: A(before)+B(before) = A(after)+B(after) (m)(v) +(m)(v) = (mA + mB)(v)
Situation 2: Ball B travels twice the velocity of ball A. 2. a. What will be the velocity of ball B after, if: a. the collision is perfectly elastic? You may use this formula: A(before)+B(before) = A(after)+B(after) (m)(v) +(m)(v) = (m)(v) +(m)(v)
2.b. What will be the velocity of ball B after, if the collision is perfectly inelastic? You may use this formula. A(before)+B(before) = A(after)+B(after) (m)(v) +(m)(v) = (mA + mB) (v)
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Answer:-
According to law of conversion of linear momentum.