a disc of large radius having moment of inertia 10kgm^2 is rotating with angular velocity 10rad/sec , about an axis perpendicular to the plane and passing through it's centre .if a point mass of 1kg I'd gently put on the disc at 2m from the centre of disc then it's new angular velocity will be ?
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Answer:
Moment of inertia I=
2
mr
2
=
2
10×0.2
2
=0.2 kgm
2
Angular acceleration α=
I
τ
=
0.2
10
=50 rad/s
2
Initial angular velocity w
i
=0
Using w
f
=w
i
+αt
Or w
f
=0+50×6=300 rad/s