Answer:
From the options itself it is clear that only in option C, when you add PE and KE i.e 2E
o
+(−E
) we get E
Now
Total energy E
=P.E+K.E=
R
−GMm
+
2
1
mv
When we substitute v=
GM
in K.E, we have K.E=
2R
GMm
∴
=E
⇒
=2E
So, P.E=
and K.E=
=−E
artificial satellite moving in a circular orbit around the Earth has total mechanical energy as E . It's kinetic energy will be ?
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Answers & Comments
Answer:
From the options itself it is clear that only in option C, when you add PE and KE i.e 2E
o
+(−E
o
) we get E
o
Now
Total energy E
o
=P.E+K.E=
R
−GMm
+
2
1
mv
2
When we substitute v=
R
GM
in K.E, we have K.E=
2R
GMm
∴
R
−GMm
+
2R
GMm
=E
o
⇒
R
−GMm
=2E
o
So, P.E=
R
−GMm
=2E
o
and K.E=
2R
GMm
=−E
o
Answer:
artificial satellite moving in a circular orbit around the Earth has total mechanical energy as E . It's kinetic energy will be ?