Answer:

Here is your answer: Acceleration =change in velocity /time. So acceleration=(98-65)/ 12=33/12=2.75m per sec sq.

Yes from Your following But unknown,

:D

Answer:

The distance covered by the body is 978 m.

Explanation:

We have given that,

• Initial velocity ( u ) = 65 m/s
• Final velocity ( v ) = 98 m/s
• Time ( t ) = 12 s
• Acceleration ( a ) = 2.75 m/s²

We have to find the distance ( s ) covered by the body.

Now, by second equation of motion,

s = ut + ½ at²

⇒ s = ( 65 * 12 ) + ½ [ 2.75 * ( 12 )² ]

⇒ s = ( 65 * 12 ) + ½ ( 2.75 * 12 * 12 )

⇒ s = 12 [ 65 + ( 2.75 * 12 ÷ 2 ) ]

⇒ s = 12 ( 65 + 2.75 * 6 )

⇒ s = 12 ( 65 + 16.5 )

⇒ s = 12 * 81.5

⇒ s = 978 m

∴ The distance covered by the body is 978 m.