A 5.3 x 10² g cart moves on an air track at 2.3m/s. It collides with and sticks to another cart of mass 6 x 10² g. which was stationary before collision? what is the velocity of the combined cart after collision?
A 5.3 x 10² g cart moves on an air track at 2.3m/s. It collides with and sticks to another cart of mass 6 x 10² g. which was stationary before collision? what is the velocity of the combined cart after collision?
Cart 1 mass
5.3 x 10² g = 530 g
530 g × 1 kg / 1000 g = 0.53 Kg
Another Cart mass
6 x 10² g = 600 g
600 g × 1 kg / 1000 g = 0.6 Kg
Before Collision After Collision
Given: Mass Velocity Mass Velocity
Cart 1 0.53 kg 2.3 m/s 0.53 kg ?
Another Cart 0.6 kg 0 m/s 0.6 kg ?
Solution:
The momentum of both cart is conserved. There is no change in the
momentum of the system before and after collision.
Total Initial Momentum = Total Final Momentum
(0.53 kg × 2.3 m/s) + (0.6 kg×0 m/s) = (0.53 kg +0.6 kg) × Vf
1.219 kg.m/s + 0 kg.m/s = 1.13 kg × Vf
1.219 kg.m/s / 1.13 kg = Vf
1.079 m/s = Vf
Answer:
The velocity of the combined cart after collision is 1.079 m/s
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Problem:
A 5.3 x 10² g cart moves on an air track at 2.3m/s. It collides with and sticks to another cart of mass 6 x 10² g. which was stationary before collision? what is the velocity of the combined cart after collision?
Cart 1 mass
5.3 x 10² g = 530 g
530 g × 1 kg / 1000 g = 0.53 Kg
Another Cart mass
6 x 10² g = 600 g
600 g × 1 kg / 1000 g = 0.6 Kg
Before Collision After Collision
Given: Mass Velocity Mass Velocity
Cart 1 0.53 kg 2.3 m/s 0.53 kg ?
Another Cart 0.6 kg 0 m/s 0.6 kg ?
Solution:
The momentum of both cart is conserved. There is no change in the
momentum of the system before and after collision.
Total Initial Momentum = Total Final Momentum
(0.53 kg × 2.3 m/s) + (0.6 kg×0 m/s) = (0.53 kg +0.6 kg) × Vf
1.219 kg.m/s + 0 kg.m/s = 1.13 kg × Vf
1.219 kg.m/s / 1.13 kg = Vf
1.079 m/s = Vf
Answer:
The velocity of the combined cart after collision is 1.079 m/s