Chris received a pat on his back from his best friend with a speed of 2m/s. If his friend's mass is about 40kg determine the kinetic energy that was within that pat.
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Answer:
KE=1/2mv^2
=1/2(40)(2m/s)^2
=1/2(40)(4m^2/s^2)
=160m^2/s^2/2
=80Nm=80J
Explanation: