how do you find the probability of the two events if: 1.)they have common element/s? 2.)they have no common elements? 3.)event A is a subset of event B? Connect the question above in the numbers to answer.. Needed lng po
The general probability addition rule for the union of two events states that P(A∪B)=P(A)+P(B)−P(A∩B) P ( A ∪ B ) = P ( A ) + P ( B ) − P ( A ∩ B ) , where A∩B A ∩ B is the intersection of the two sets. The addition rule can be shortened if the sets are disjoint:
1
Hydrogen. Created during the hot Big Bang but depleted by stellar fusion, ~70% of the Universe remains hydrogen.
Helium. About 28% is helium, with 25% formed in the Big Bang and 3% from stellar fusion.
Oxygen. ...
Carbon. ...
Neon. ...
Nitrogen. ...
Magnesium. ...
Silicon.
2.Two sets are disjoint if they have no elements in common, i.e., if their intersection is the empty set. ... B ∩ C = ∅, so B and C are disjoint. A and B have elements in common, so they are not disjoint. Also, A and C are not disjoint.
3.We say that an event A is a subset of an event B, and write A⊆B, when all outcomes in A are also in B. For example, suppose two dice are rolled.
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Answer:
The general probability addition rule for the union of two events states that P(A∪B)=P(A)+P(B)−P(A∩B) P ( A ∪ B ) = P ( A ) + P ( B ) − P ( A ∩ B ) , where A∩B A ∩ B is the intersection of the two sets. The addition rule can be shortened if the sets are disjoint:
1
2.Two sets are disjoint if they have no elements in common, i.e., if their intersection is the empty set. ... B ∩ C = ∅, so B and C are disjoint. A and B have elements in common, so they are not disjoint. Also, A and C are not disjoint.
3.We say that an event A is a subset of an event B, and write A⊆B, when all outcomes in A are also in B. For example, suppose two dice are rolled.
Step-by-step explanation:
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