Verified answer

A. The resistance in the circuit will not be changed or affected.

If adding a load/s in a series circuit, the resistance will not be changed or affected while the current itself decreased.

If you can see in this example, I will add loads, and we will compute how much current being decreased to the resistance.

LEGEND:

V= referring to Voltage

Ω/R= referring to Resistance

A/I= referring to Current

Let's compute with 1 load and see the result!

Given:

12 V, 4 Ω

The formula for solving current:

I = V/R

The solution and the answer:

12/4 = 3 A

Let's see if I add two loads into the series circuit!

Given:

12 V, 8 Ω

The formula for solving current:

I = V/R

The solution and the answer:

12/8 = 1.5 A

A big difference!

When I add 1 load to the circuit, the current will be 3 A, if I add 2 loads to the circuit, it will result in 1.5 A.

Review!

We see that the current with 1 load (3 A) drops down by 1.5 A with 2 loads.

We can see the current itself decreases when we add more loads to it.

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