Answer:
Step-by-step explanation:
Solution :-
In Square PQRS, side a = 28 m.
In two semi-circles,
PQ and RS are diameters.
So, PQ = RS = 28 m
r = 28/2 = 14 m
Area of uncovered portion = Area of square PQRS - 2 × Area of semi-circles.
Area of uncovered portion = a² - 2 × πr²/2
Area of uncovered portion = 28² - 22/7 × 14 × 14
Area of uncovered portion = 274 - 616
Area of uncovered portion = 168 m²
Hence, 168 m² area will be left uncovered.
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Answers & Comments
Answer:
Step-by-step explanation:
Solution :-
In Square PQRS, side a = 28 m.
In two semi-circles,
PQ and RS are diameters.
So, PQ = RS = 28 m
r = 28/2 = 14 m
Area of uncovered portion = Area of square PQRS - 2 × Area of semi-circles.
Area of uncovered portion = a² - 2 × πr²/2
Area of uncovered portion = 28² - 22/7 × 14 × 14
Area of uncovered portion = 274 - 616
Area of uncovered portion = 168 m²
Hence, 168 m² area will be left uncovered.
Verified answer
Lenght of side of square=28mArea of the square=(side)^2 sq. unit
=(28^2)m^2
=784m^2
Since lenght of side of square is 28m
Diameter of the semicircles=28m
Radius of the semicircles=14m
Area of a semicircle=1/2*pi*r*r sq. unit
Area of both the semicircles=(2*1/2*pi*r*r)sq. unit
=pi*r*r sw. unit
=22/7×14×14 m^2
=616 m^2
After covering left area=(784-616) m^2
=168 m^2