find the area of the triangle whose sides are 42cm,34cm and 20cm. Also find the height corresponding to the longest side.
Answers & Comments
Xosmos
Semiperimeter (s) = (42 + 34 + 20 ) / 2 So it is = 96 / 2 = 48 cm.
Using herons formula = (√s )(√s-a )(√s-b) (√s-c) By substituting s and a , b , c i.e the given sides. We have √48 × √6 × √14 × √28 So √ (4 × 6 × 2) × √6 × √(7 × 2) × √(7 × 4) Simplifying the numbers we have area = 4 × 6 × 2 × 7 = 336 cm ² Hence area is 336 cm²
Now height corresponding to longest side implies that base is 42 cm and area remains same
So area of triangle is 1/ 2 b × h 336 = 1/ 2 × 42 × H HENCE H = 16 cm
Answers & Comments
So it is = 96 / 2 = 48 cm.
Using herons formula = (√s )(√s-a )(√s-b) (√s-c)
By substituting s and a , b , c i.e the given sides.
We have √48 × √6 × √14 × √28
So √ (4 × 6 × 2) × √6 × √(7 × 2) × √(7 × 4)
Simplifying the numbers we have area = 4 × 6 × 2 × 7 = 336 cm ²
Hence area is 336 cm²
Now height corresponding to longest side implies that base is 42 cm and area remains same
So area of triangle is 1/ 2 b × h
336 = 1/ 2 × 42 × H
HENCE H = 16 cm
So height is 16 cm .