Answer:
In △ABD, ∠ABD + ∠ADB + ∠DAB = 180° [angle sum property of triangle]
50° + ∠ADB + 60° = 180°
⇒ ∠ADB = 70°
Now, ∠ACB = ∠ABD = 70° [∵ angle in same segment]
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Answer:
In △ABD, ∠ABD + ∠ADB + ∠DAB = 180° [angle sum property of triangle]
50° + ∠ADB + 60° = 180°
⇒ ∠ADB = 70°
Now, ∠ACB = ∠ABD = 70° [∵ angle in same segment]