Answer:

let AB be the chord of the circle with centre O and radius 13cm such that AB=10 cm

from O,draw the OL parallel to AB.join A

since,the perpendicular form of a centre of circle to chord bisects the chord

therefore,AB=LB=½AB=5cm

now in right angle triangle, OLA we have

OA²=OL²+AL²

13²=OL²+5²

13²-5²=OL²

OL²=144cm

OL= 12cm

Hence the distance of the chord from the centre is 12cm

Hope it will help you....