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On dividing the polynomial 3y^3-4y^2-3y+25 by a polynomial g(y) the quotient and remainder were 3y+5 and 5 respectively .find g(y)
On dividing the polynomial 3y^3-4y^2-3y+25 by a polynomial g(y) the quotient and remainder were 3y+5 and 5 respectively .find g(y)
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dividend =divisior×quotient+remainder
3y³-4y²-3y+25=g(y)×(3y+5) +5
g(y)=(3y³-4y²-3y+20)/(3y+5)
g(y)=y²-3y+4
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