we have to find the pH of 10¯³ M KOH solution.
dissociation reaction of KOH is..
KOH ⇔ K⁺ + OH¯
we see, one mole of KOH forms 1 mole of OH¯ ions.
so, concentration of OH¯ = [OH¯] = 10¯³ M
we know,
ionic product of water , kw = [H⁺][OH¯] = 10¯¹⁴
so, [H⁺] × 10¯³ = 10¯¹⁴
⇒[H⁺] = 10¯¹¹ M
from Arrhenius formula, pH = -log[H⁺]
= -log(10¯¹¹) = 11
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we have to find the pH of 10¯³ M KOH solution.
solution :
dissociation reaction of KOH is..
KOH ⇔ K⁺ + OH¯
we see, one mole of KOH forms 1 mole of OH¯ ions.
so, concentration of OH¯ = [OH¯] = 10¯³ M
we know,
ionic product of water , kw = [H⁺][OH¯] = 10¯¹⁴
so, [H⁺] × 10¯³ = 10¯¹⁴
⇒[H⁺] = 10¯¹¹ M
from Arrhenius formula, pH = -log[H⁺]
= -log(10¯¹¹) = 11
Therefore the pH of 10¯³ M KOH is 11