Rhombus SAMT with m∠STM = (3x + 11)°

Solution:

m∠STM = (3x + 11)

Since there is only one given equation, which is 3x + 11,

Assuming triangle TSM is an equilateral triangle  from triangle STM

m∠STM = (3x + 11)

m∠STM = 3(49/3) + 11

m∠STM = 49 +11

m∠STM = 60°

• m∠STM = 60°

m∠MTA = m∠STM/2

m∠MTA = 60/2

m∠MTA = 30°

• m∠MTA = 30°

m∠TSA = 60 + 60

m∠TSA = 120°

• m∠TSA = 120°

m∠TSM = m∠TSA /2

m∠TSM = 120/2

m∠TSM = 60°

• m∠TSM = 60°

Answer:

3.) m∠MTA = 30°

4.) m∠TSM = 60°

Square FGHI

Solution:

m∠IFG = 90°

• m∠IFG = 90°

m∠JFG = m∠IFG/2

m∠JFG = 90/2

m∠JFG = 45°

• m∠JFG = 45°

Answer:

5.) m∠JFG = 45°

Hope It Helps

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