mPA = mLS
5x - 14 = 4x + 6
5x - 4x = 6 + 14
x = 20
mPA = 5x - 14
mPA = 5(20) - 14
mPA = 100 - 14
mPA = 86 cm
mPM = mPA/2
mPM = 86/2
mPM = 43 cm
mSL = mLS = 4x + 6
mSL = 4x + 6
mSL = 4(20) + 6
mSL = 80 + 6
mSL = 86
1.) mPM = 43 cm
2.) mSL = 86
m∠STM = (3x + 11)
Since there is only one given equation, which is 3x + 11,
Assuming triangle TSM is an equilateral triangle from triangle STM
m∠STM = 3(49/3) + 11
m∠STM = 49 +11
m∠STM = 60°
m∠MTA = m∠STM/2
m∠MTA = 60/2
m∠MTA = 30°
m∠TSA = 60 + 60
m∠TSA = 120°
m∠TSM = m∠TSA /2
m∠TSM = 120/2
m∠TSM = 60°
3.) m∠MTA = 30°
4.) m∠TSM = 60°
m∠IFG = 90°
m∠JFG = m∠IFG/2
m∠JFG = 90/2
m∠JFG = 45°
5.) m∠JFG = 45°
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Answers & Comments
Find the measure of the unknown angles and sides of the given parallelogram as shown in the figure below:
Rectangle PSAL has a diagonal mPA = 5x - 14 cm and mLS = 4x + 6 cm
Solution:
mPA = mLS
5x - 14 = 4x + 6
5x - 4x = 6 + 14
x = 20
mPA = 5x - 14
mPA = 5(20) - 14
mPA = 100 - 14
mPA = 86 cm
mPM = mPA/2
mPM = 86/2
mPM = 43 cm
mSL = mLS = 4x + 6
mSL = 4x + 6
mSL = 4(20) + 6
mSL = 80 + 6
mSL = 86
Answer:
1.) mPM = 43 cm
2.) mSL = 86
Rhombus SAMT with m∠STM = (3x + 11)°
Solution:
m∠STM = (3x + 11)
Since there is only one given equation, which is 3x + 11,
Assuming triangle TSM is an equilateral triangle from triangle STM
m∠STM = (3x + 11)
m∠STM = 3(49/3) + 11
m∠STM = 49 +11
m∠STM = 60°
m∠MTA = m∠STM/2
m∠MTA = 60/2
m∠MTA = 30°
m∠TSA = 60 + 60
m∠TSA = 120°
m∠TSM = m∠TSA /2
m∠TSM = 120/2
m∠TSM = 60°
Answer:
3.) m∠MTA = 30°
4.) m∠TSM = 60°
Square FGHI
Solution:
m∠IFG = 90°
m∠JFG = m∠IFG/2
m∠JFG = 90/2
m∠JFG = 45°
Answer:
5.) m∠JFG = 45°
Hope It Helps
#CarryOnLearning
#KeepOnLearning