Answer:

1. Diamond: 12/52

Face card: 12/52

King: 4/52

Any of the three: 12 + 12 + 4= 28/52= 7/13 = 53.8%

2. ● 217.5 pesos

● 1916 2/3÷2=958 1/3 pesos each sack of rice.

● The sunflowers and roses Lira have altogether is 45.

● 6 1/4 kilos of fruits.

● Edna could sew faster than Eva by 1 1/6 hours.

3. The problem asks to find the probability of selecting either a queen or a diamond

There are 52 cards in a standard deck.

Since there are 13 diamonds in a standard deck, the probability of drawing a diamond is

P(diamond) = 13/52

P(diamond) = 1/4

Since there are 4 queens in a standard deck, the probability of drawing a queen is

P(queen) = 4/52

P(queen) = 1/13

Since there is only 1 card that is both diamond and queen (queen of diamonds), the probability of drawing that is

P(diamond and queen) = 1/52

Solving for the probability of drawing a diamond or a queen

P(diamond or queen) = P(diamond) + P(queen) - P(diamond and queen)

P(diamond or queen = (1/4) + (1/13) - (1/52)

P(diamond or queen) = 4/13

Therefore, the probability of drawing a diamond or a queen is 4/13.