Answer:
1. c+d
2. 15 000.00 [25x^2-30x+9} PHP
Explanation:
1.
Solution:
Area= L•W {formula}
= (c²+2cd+d²)•(c+d)
= (c+d)²•(c+d)
= (c+d)³
The Minimum number= (c+d)³
————
(c+d)²
= c+d
Answer: c+d
2.
A=L^2
=[5x-3]^2;
Since no other arrangement to manipulate the value of x, we will leave our answer with variable x...
a.) How many meters of fencing materials to enclosed the square lot
- means we have to compute the distance of the square or it's PERIMETER.
P=21+2w;
since it's a square;
L=w;
P= 21+21
=41;
=4[5x-2]:
P=20x-8
b.) 1m^2= is cost PHP 15,000.00
A= 1^[cost per m^2]
Cost= 15,000.00 {5x-3]^2
= 15,000.00 [25x^2-30x+9}php... ans;
Answer: 15,000.00 [25x^2-30+9] or PHP 15,000.00[25x^2-30+9]
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Answers & Comments
Answer:
1. c+d
2. 15 000.00 [25x^2-30x+9} PHP
Explanation:
1.
Solution:
Area= L•W {formula}
= (c²+2cd+d²)•(c+d)
= (c+d)²•(c+d)
= (c+d)³
The Minimum number= (c+d)³
————
(c+d)²
= c+d
Answer: c+d
2.
A=L^2
=[5x-3]^2;
Since no other arrangement to manipulate the value of x, we will leave our answer with variable x...
a.) How many meters of fencing materials to enclosed the square lot
- means we have to compute the distance of the square or it's PERIMETER.
P=21+2w;
since it's a square;
L=w;
P= 21+21
=41;
=4[5x-2]:
P=20x-8
b.) 1m^2= is cost PHP 15,000.00
A= 1^[cost per m^2]
Cost= 15,000.00 {5x-3]^2
= 15,000.00 [25x^2-30x+9}php... ans;
Answer: 15,000.00 [25x^2-30+9] or PHP 15,000.00[25x^2-30+9]