one of the digit of a two digit number is twice the other digit the sum of the o...

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September 2021 2 25 Report

one of the digit of a two digit number is twice the other digit the sum of the original number and the number formed by reversing the digits is 99 find the number

sooryansh59 Let the digit at ones place be x
digit at tens place= 2x
original number= 20x+x
=21x
reversed digit number= 10x+2x
=12x
so
21x+12x=99
33x=99
x=3
Number= 21x = 21×3=63

sooryansh59 pls nark brainliest

sooryansh59 mark

sooryansh59 :)

AdiN05517 Hi friend!

$Answer:$

The two digits = x and y
Original number = 10x + y
Reversed number = 10y + x

One of the digits is twice the other:
y = 2x

Sum of original and reversed number is 99:
10x + y + 10 y + x = 99
$11x + 11y = 99 \\ 11x + 11(2x) = 99 \\ 11x + 22x = 99 \\ 33x = 99 \\ x = \frac{99}{33} \\ x = 3$

Original number =
$10x + y = 10x + 2x = 12x = 12(3) = 12 \times 3 \\ = 36$

Note: If we take 'x = 2y' instead of 'y = 2x' then we'll get the answer as 63.
Both the answers 36 and 63 are correct for this question.

Hope you found my answer helpful. Keep Smiling!

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