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harshit8445
@harshit8445
September 2021
1
22
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find the value of 'm' so that (2x-3) is a factor 6x3 -x3-10x+m
Answers & Comments
Mankuthemonkey01
First of all we have to find the zero of the divisor
so zero of divisor is
2x - 3 = 0
=> 2x = 3
=> x = 3/2
If (2x - 3) is a factor of (6x³ - x² - 10x + m) then by remainder theorem, remainder will be zero.
=> Putting the value of x we get
6(3/2)³ - (3/2)² - 10(3/2) + m = 0
=> 81/4 - 9/4 - 15 + m = 0
=> 81/4 - 9/4 - 60/4 + m = 0
=> 12/4 + m = 0
=> 3 + m = 0
=> m = (-3)
Hope it helps dear friend ☺️✌️
1 votes
Thanks 5
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Answers & Comments
so zero of divisor is
2x - 3 = 0
=> 2x = 3
=> x = 3/2
If (2x - 3) is a factor of (6x³ - x² - 10x + m) then by remainder theorem, remainder will be zero.
=> Putting the value of x we get
6(3/2)³ - (3/2)² - 10(3/2) + m = 0
=> 81/4 - 9/4 - 15 + m = 0
=> 81/4 - 9/4 - 60/4 + m = 0
=> 12/4 + m = 0
=> 3 + m = 0
=> m = (-3)
Hope it helps dear friend ☺️✌️