◆ Explanation -

Fe2+ in ferrous oxalate is oxidised to Fe3+ by acidified K2Cr2O7.

The reaction takes place as follows -

K2Cr2O7 + 7H2SO4 + 2FeC2O4 → Fe2(SO4)3 + K2SO4 + Cr2(SO4)3 + 4CO2 + 7H2O

That is, each mole of K2Cr2O7 oxidises 2 moles of ferrous sulphate.

Hence, to oxidize 2 moles of FeSO4, only 1 mole of K2Cr2O7 is required.

Answer:

2.17 MOLES

Explanation:

MOLECULAR MASS OF feso4 = 152

MOLECULAR MASS OF k2cr2o7 = 256

SO, required mole = 256/152 = 2.17