Answer:
option 'c' is correct option
Explanation:
hope it will help
The magnetic flux that links the larger loop with the smaller loop of side l is
Φ₁₂ = Bl² = (2√2μ₀IL²)/πL
∴ Mutual Inductance M₁₂ :
= Φ₁₂/I
= (2√2μ₀/π) * (l²/L)
∴ M₁₂ ∝ (I²/L)
Hope it helps!
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Answers & Comments
Answer:
option 'c' is correct option
Explanation:
hope it will help
Explanation:
The magnetic flux that links the larger loop with the smaller loop of side l is
Φ₁₂ = Bl² = (2√2μ₀IL²)/πL
∴ Mutual Inductance M₁₂ :
= Φ₁₂/I
= (2√2μ₀/π) * (l²/L)
∴ M₁₂ ∝ (I²/L)
Hope it helps!