Kindly solve with explaination.Thanks.Plus, don't try to spam!Moderator's account.. Created by Mankuthemonkey01. Math

Kindly solve with explaination.Thanks.Plus, don't try to spam!Moderator's accoun...

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October 2021 2 67 Report

Kindly solve with explaination.

Thanks.

Plus, don't try to spam!
Moderator's account.

SillySam $HEYA MATE, HERE IS UR ANSWER$

$\frac{Cos 13+ Sin 13}{Cos 13- Sin 13}$

Dividing both numerator and denominator by Cos 13.

= $\frac{cos13}{Cos 13}$ + $\frac {Sin13}{Cos 13}$ / $\frac {cos13}{Cos 13}$ - $\frac {Sin 13}{Cos 13}$

= $\frac {1+Tan 13}{1-Tan 13}$ -----(as Sin A/Cos A =Tan A)

We can write 1= Tan 45 .

= $\frac{Tan 45 + Tan 13}{1-1×Tan 13}$

= $\frac {Tan 45+Tan 13}{1-Tan45 Tan13}$

the expression coming is similar to tangent of a compound angle .

So ,By sum formula of Tangent

Tan (45+13)

=>Tan58 =Tan A

Comparing both the sides

A=58 .

Warm regards

@laughterqueen

$\huge\boxed{\mathbb{BE\:BRAINLY}}$

Mankuthemonkey01 Dhanywad. All doubts clear. Thanks a loooooootttttttttt Behenjaan ❤️ :)

SillySam mention not...when bhenjaan is there ..no fear. .xD

adee1729 Divide numerator and denominator by cos13°,
then we have

(1+tan13°)/(1-tan13°) = tanA,

we can write it as,

(tan45°+tan13°)/(1-tan45°.tan13°) = tanA,

then it becomes

tan(45°+13°) = tanA,

tan58° = tanA,

then

A=58°

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