keeping the potential difference constant ,the resistance of the circuit is doubled.By how much does the current change?
Answers & Comments
amlan99
As from Ohm's Law, V = IR........1 Now, here V is constant. Let , new resistance R' = 2R and assume that current flow be I' So, from 1, IR = I'.R', -> IR = I'.2R, Therefore, I' = I / 2
Answers & Comments
V = IR........1
Now, here V is constant.
Let , new resistance R' = 2R and assume that current flow be I'
So, from 1,
IR = I'.R',
-> IR = I'.2R,
Therefore, I' = I / 2
So the current is halved.
Answer:
According to ohm's law
R =v/I...............(1) ( R=resistance, V=voltage , I =current )
let I' be the current when Resistance become double
2R = V/I' ............(2) (V is constant)
dividing equation (2) by (1)
R/2R= (V/I)/V/I'
1/2=I'/I
I=2I'
I/2=I'
Current through conductor become half