Verified answer

a. T = 3.16 x 10⁷ s

b. f = 3.16 x 10⁻⁸/s

c. ω = 1.987 x 10⁻⁷ rad/s

Further explanation  

Period(T) is the time it takes for an object to make a single vibration

Frequency(f) is the number of vibrations that an object makes in one second.

Given

365.25 days revolution of the earth

Required

a)period

b)frequency

c)angular frequency

Solution

• Period

T = 365.25 days x 24 hours/days x 3600 s/hour

T = 3.16 x 10⁷ s

• Frequency

f = n/t = 1/T

n = number of vibrations

t = time

Input the value :

• Angular frequency = angular velocity

The speed of the rotating object is called angular velocity. This value is part of circular motion.  

The angular velocity is denoted by ω including the vector quantity. The unit used is usually rpm (rotation per minute) or radians/sec

Average angular velocity is the ratio of angular displacement to the time interval

Can be formulated :

ω =  Δθ / Δt

or

ω = 2πf=2π/T

Input the value :

Learn more

The angular acceleration  

brainly.ph/question/1670560

the probe’s velocity relative to the earth  

brainly.ph/question/1467317  

Uniformly accelerated motion: the vertical dimension  

brainly.ph/question/2098492  

#LetsStudy